Jack The Ripper Forums  - Ripperology For The 21st Century  

Go Back   Jack The Ripper Forums - Ripperology For The 21st Century > JTRForums Competition Forum

Reply
 
Thread Tools Search this Thread Display Modes
Old March 21st, 2013, 07:43 AM   #11
Caroline Brown
Author
 
Caroline Brown's Avatar
 
Join Date: Sep 2005
Posts: 5,138
Default

Quote:
Originally Posted by Iselio De Lisi View Post
1 cat eats 1 mice in 1 minut
Ah, so 3 cats each eat 3 meeces to pieces in 3 minutes, making a total of 9 meeces between them.

Therefore 100 cats would each eat 100 meeces to pieces in 100 minutes, making a total of 300 meeces.

So in fact, you would need 33.3 recurring cats to eat a total of 100 meeces to pieces in 100 minutes.

Who's going to cut that last cat into thirds? And will he lose his appetite?
__________________
I wish I were two puppies then I could play together - Storm Petersen
Caroline Brown is offline   Reply With Quote
Old March 21st, 2013, 07:48 AM   #12
Phil Carter
Author
 
Join Date: Nov 2009
Posts: 1,755
Default

Quote:
Originally Posted by Nemo View Post
That WAS the explanation - lol

1 cat eats 1 mouse in 3 minutes so 3 cats eat 3 mice in 3 minutes, therefore 3 cats eat 1 mouse between them in 1 minute

So 3 cats eat 100 mice in 100 minutes

Is this a trick question?
Nemo...were the cats just pussyfooting around?

For the mice, a certain catastrophy

And for Robert..

our's is a nice 'ouse our's is, it's got no cats nor mouses.


Phil
__________________
from 1905...to 19.05..it was written in the stars
Phil Carter is offline   Reply With Quote
Old March 21st, 2013, 09:06 AM   #13
Robert Linford
Researcher Extraordinaire
 
Robert Linford's Avatar
 
Join Date: Sep 2005
Posts: 18,750
Default

If a cat eats one mouse per minute, then for 100 mice to be eaten in 100 minutes, you need one cat. So the answer is one.
Robert Linford is offline   Reply With Quote
Old March 21st, 2013, 09:21 AM   #14
Paul Kearney A.K.A. NEMO
Theorist & Speculator
 
Paul Kearney A.K.A. NEMO's Avatar
 
Join Date: Feb 2008
Location: Shropshire UK
Posts: 6,516
Default

That's a different parameter though Robert - I think Iselio must have made a mistake as 3 cats eating 3 mice in 3 mins is not the same as 1 cat eating 1 mouse per minute
Paul Kearney A.K.A. NEMO is offline   Reply With Quote
Old March 21st, 2013, 09:28 AM   #15
Robert Linford
Researcher Extraordinaire
 
Robert Linford's Avatar
 
Join Date: Sep 2005
Posts: 18,750
Default

Hi Nemo

Maybe Iselio meant 3 cats each eat 3 mice in three minutes, with each cat eating one mouse per minute.

Or maybe he's playing cat and mouse with us.
Robert Linford is offline   Reply With Quote
Old March 21st, 2013, 09:40 AM   #16
Phil Carter
Author
 
Join Date: Nov 2009
Posts: 1,755
Default

Kit-Kat anyone? Sugared mice?


Phil
__________________
from 1905...to 19.05..it was written in the stars
Phil Carter is offline   Reply With Quote
Old March 21st, 2013, 10:16 AM   #17
Robert Linford
Researcher Extraordinaire
 
Robert Linford's Avatar
 
Join Date: Sep 2005
Posts: 18,750
Default

I think it would be easier if it was "Howard Brown eats 100 burgers in 3 minutes."
Robert Linford is offline   Reply With Quote
Old March 21st, 2013, 10:16 AM   #18
Iselio De Lisi
Registered User
 
Iselio De Lisi's Avatar
 
Join Date: Feb 2013
Posts: 83
Default

Some have already given the answer, but the mathematical explanation is not yet complete.

Carolina you are tremendously close to the answer. If you cancel your question and invert his terms you will get the enlightenment the explanation too. (If you prefer, instead of the photo of burlesque dancer you can get the photo of one handsome man).

Nemo any "trick question?".
__________________
in medio stat virtus
Iselio De Lisi is offline   Reply With Quote
Old March 21st, 2013, 03:50 PM   #19
Howard Brown
Proprietor-Administrator
 
Join Date: Jul 2003
Location: Eagleville, Pa.
Posts: 74,719
Default

I think it would be easier if it was "Howard Brown eats 100 burgers in 3 minutes." ---My buddy Robert

No...that's too easy. Make it 10 cheese steaks in 10 minutes.
__________________
To Join JTR Forums, Contact :
Howard@jtrforums.com
Howard Brown is online now   Reply With Quote
Old March 21st, 2013, 06:14 PM   #20
Iselio De Lisi
Registered User
 
Iselio De Lisi's Avatar
 
Join Date: Feb 2013
Posts: 83
Default

The Solution:

The puzzle was:

Three cats are eating three mice in three minutes.
How many cats needs for eat one hundred mice in one hundred minutes?

Math explanation.

3 cats eats 3 mice in 3 minutes = (3:1)= 1 cats, eat 1 mouse in 1 minute.

1 cat eats in 100 minutes = (100:3= 33.3333333) 33.3333333 mice

3 cat eats in 100 minutes = (mices 33.3333333 X 3) 99.9999999 mice

Simplified (for Howard)

3 cat eats in 100 minutes = 99 mice.

Remains 1 mouse, 3 cats jumps on 1 mouse, they eats 1/3 mouse each.

So for eat 100 mice in 100 minutes needs 3 cats (the tail and claws remains because they are not edible).

Caroline and Nemo are 2/3 winners. They will receive also the famous Cabinet picture.

Participants and 2/3 Winners may contact me by PM to receive the craved award.
__________________
in medio stat virtus
Iselio De Lisi is offline   Reply With Quote
Reply


Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 
Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off



All times are GMT -4. The time now is 11:28 PM.


Powered by vBulletin® Version 3.8.10 Beta 2
Copyright ©2000 - 2017, vBulletin Solutions, Inc.
Copyright @ Howard & Nina Brown 2015-2022